(3x^2-18x+24)/x-4

Solution for (3x^2-18x+24)/x-4 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x^2-(18*x)+24)/x-4 = 0

(3*x^2-18*x+24)/x-4 = 0

(3*x^2-18*x+24)/x+(-4*x)/x = 0

3*x^2-18*x-4*x+24 = 0

3*x^2-22*x+24 = 0

3*x^2-22*x+24 = 0

3*x^2-22*x+24 = 0

DELTA = (-22)^2-(3*4*24)

DELTA = 196

DELTA > 0

x = (196^(1/2)+22)/(2*3) or x = (22-196^(1/2))/(2*3)

x = 6 or x = 4/3

(x-4/3)*(x-6) = 0

((x-4/3)*(x-6))/x = 0

((x-4/3)*(x-6))/x = 0 // * x

(x-4/3)*(x-6) = 0

( x-4/3 )

x-4/3 = 0 // + 4/3

x = 4/3

( x-6 )

x-6 = 0 // + 6

x = 6

x in { 4/3, 6 }